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A pizza with diameter of 12 inches is split into 8 equally s

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A pizza with diameter of 12 inches is split into 8 equally s

by BTGmoderatorAT » Wed Sep 20, 2017 4:19 am
A pizza with diameter of 12 inches is split into 8 equally sized pieces. (There is a figure here I cannot insert for some reason: imagine a circle with 8 points on the perimeter: A through H. The center is point "O"). 4 non-adjacent pieces are removed. What is the perimeter AOBCODEOFGOHA of the pizza now, including the inside edges of the slices?

A) 48ππ+48

B) 24ππ+48

C) 24ππ+24

D) 6ππ+48

E) 6ππ+24

OA: D
Is there a strategic approach to this question?
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by DavidG@VeritasPrep » Wed Sep 20, 2017 6:42 am
ardz24 wrote:A pizza with diameter of 12 inches is split into 8 equally sized pieces. (There is a figure here I cannot insert for some reason: imagine a circle with 8 points on the perimeter: A through H. The center is point "O"). 4 non-adjacent pieces are removed. What is the perimeter AOBCODEOFGOHA of the pizza now, including the inside edges of the slices?

A) 48ππ+48

B) 24ππ+48

C) 24ππ+24

D) 6ππ+48

E) 6ππ+24

OA: D
Is there a strategic approach to this question?
If the diameter is 12, the full circumference of the circle would be 12Ï€. Because half the pieces are removed, half the circumference remains, so we've got 6Ï€.

We've got four slices left, and the length of each edge of a slice will be the radius, or 6. Each of the 4 slices has two edges, giving us a total of 8 edges, each with a length of 6, for a total of 8*6 = 48.

Total perimeter = 6Ï€ + 48. The answer is D
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