This requires us to use prime factorization.Marisa wrote:If the integers w,x,y,z is 770 and if 1<w<x<y<z. What is z?
770 = 2x5x7x11
If 1<w<x<y<z then:
w=2
x=5
y=7
z=11
Product of Integers
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770 = 2x5x7x11
If 1<w<x<y<z then:
w=2
x=5
y=7
z=11
Brent Hanneson - Creator of GMATPrepNow.com
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bluementor
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I believe the question should read:Marisa wrote:If the integers w,x,y,z is 770 and if 1<w<x<y<z. What is z?
If the product of the integers w,x,y,z is 770 and if 1<w<x<y<z. What is z?
The answer to this question would be:
w*x*y*z = 770
w*x*y*z = 10 x 77
w*x*y*z = 2x5 x 7x11
Since z is the largest factor, z must be 11.
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