The rectangle A has a by b and another rectangle B has c by

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The rectangle A has a(width) and b(height) and another rectangle B has c(width) and d(height). If a/c=b/d=3/2, what is the ratio of the rectangle A's area to the rectangle B's?

A. 3/2
B. 3/4
C. 9/2
D. 9/4
E. 27/8


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Last edited by Max@Math Revolution on Mon Apr 04, 2016 5:04 am, edited 1 time in total.
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by GMATinsight » Sun Apr 03, 2016 5:14 am
Max@Math Revolution wrote:The rectangle A has a by b and another rectangle B has c by d. If a/c=b/d=3/2, what is the ratio of the rectangle A's area to the rectangle B's?

A. 3/2
B. 3/4
C. 9/2
D. 9/4
E. 27/8


* A solution will be posted in two days.
"The rectangle A has a by b and another rectangle B has c by d"
I find it NON-GMAT LANGUAGE


a/c=b/d=3/2

i.e. a/b = c/d i.e. the two rectangles are similar rectangles

Ratio of Areas = Square of ratio of their corresponding sides

i.e. Ratio of Areas of Rectangle A and B = (a/c)^2 = (3/2)^2 = 9/4

ANswer: Option D
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by Max@Math Revolution » Mon Apr 04, 2016 5:03 am
GMATinsight wrote:
Max@Math Revolution wrote:The rectangle A has a by b and another rectangle B has c by d. If a/c=b/d=3/2, what is the ratio of the rectangle A's area to the rectangle B's?

A. 3/2
B. 3/4
C. 9/2
D. 9/4
E. 27/8


* A solution will be posted in two days.
"The rectangle A has a by b and another rectangle B has c by d"
I find it NON-GMAT LANGUAGE


a/c=b/d=3/2

i.e. a/b = c/d i.e. the two rectangles are similar rectangles

Ratio of Areas = Square of ratio of their corresponding sides

i.e. Ratio of Areas of Rectangle A and B = (a/c)^2 = (3/2)^2 = 9/4

ANswer: Option D
Sorry about the mistake. I have revised the question.

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by Max@Math Revolution » Tue Apr 05, 2016 5:02 am
The rectangle A has a(width) and b(height) and another rectangle B has c(width) and d(height). If a/c=b/d=3/2, what is the ratio of the rectangle A's area to the rectangle B's?

A. 3/2
B. 3/4
C. 9/2
D. 9/4
E. 27/8


-> a=3k, c=2, and b=3m, d=2m
Then, the ratio of the area is (3k)(3m):(2k)(2m)=9km:4km=9:4=9/4
Hence, the answer is D.