BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem
TTP OnDemand GMAT Video Course
Featured Course

Target Test Prep GMAT OnDemand

Scott Woodbury-Stewart’s private virtual classroom — 400 hours of master-class video lessons for the GMAT Focus Edition.

  • 715+ score guarantee — highest in the industry (99th percentile)
  • 52 chapters · 1,500+ lessons · 4,000+ practice questions
  • 400 hours of video · 1,500+ instructor-led HD smartboard lessons
  • 300,000+ students accepted to Harvard, Stanford, Wharton, Booth & Sloan & more
  • 24/7 live support + weekly Zoom office hours with GMAT instructors
  • TTP AI Assist — 24/7 AI-powered virtual tutor for instant help
  • 1,200+ flashcards + AI-powered study assistant & daily calendar
  • OnDemand, LiveTeach & GMAT Bootcamp formats available
  • Also: GRE, SAT Math & Executive Assessment courses
  • MBA Admissions Consulting now available
  • 🏆 2025 EdTech Breakthrough Award: Test Prep Solution Provider of the Year
  • 200,000+ students served
  • 5-day free trial — $0 to start, no auto-billing, cancel anytime
★★★★★ 5.0 (559 reviews)
130-pt guarantee
$0 to start then $127/mo
Start Free 5-Day Trial Read 559 Reviews →

Interger

Expert replies
Post new topic Post Reply
Previous Topic Next Topic
Source: — Problem Solving |
Master | Next Rank: 500 Posts
Posts: 247
Joined: Sun Jul 27, 2008 1:39 am
Thanked: 2 times
GMAT Score:660

by orel » Sun Nov 23, 2008 8:07 am
isn't it 16?

0<=3n+1<=50
n<=16
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Legendary Member
Posts: 891
Joined: Sat Aug 16, 2008 4:21 amFollowed by: 1 member
Thanked: 27 times
GMAT Score:660(

by 4meonly » Sun Nov 23, 2008 8:07 am
the least integer that will satisfy given options is 1
the greates - 49
49-1 /3 = 16
do not forget to add 1
16+1 = 17
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Master | Next Rank: 500 Posts
Posts: 247
Joined: Sun Jul 27, 2008 1:39 am
Thanked: 2 times
GMAT Score:660

by orel » Sun Nov 23, 2008 8:40 am
4meonly wrote:the least integer that will satisfy given options is 1
the greates - 49
49-1 /3 = 16
do not forget to add 1
16+1 = 17
hi!

how the remainder can be 1 when 1 is devided by 3? so, the least integer satisfying the option is 4.
but even if we count one by one, the integers satisfying the option are:

4, 7,10,13,16,19,22,25,28,31,34,37,40,43,46,49
so, 16
am i missing smth???
please, explain!!!
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Legendary Member
Posts: 891
Joined: Sat Aug 16, 2008 4:21 amFollowed by: 1 member
Thanked: 27 times
GMAT Score:660(

by 4meonly » Sun Nov 23, 2008 11:41 am
Yes, u still miss 1
How many integers from 0 to 50, inclusive, have a remainder of 1 when divided by 3 ?

n=3q+1
where n - your integer
3 - factor
Q- quotent
1 - remainder
you should find the number of n that are 0<n<50

4=3*1 +1
7=3*2 +1
10 = 3*3 +1

and 1 = 3*0 +1

OK?
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
User avatar
Legendary Member
Posts: 2134
Joined: Mon Oct 20, 2008 11:26 pmFollowed by: 25 members
Thanked: 237 times
GMAT Score:730

by logitech » Sun Nov 23, 2008 2:05 pm
if you divide X with Y

and

X < Y

The remainder is X itself.

Ex:

3 is divided by 4

the remainder is 3

1 is divided by 3

the remainder is 1
LGTCH
---------------------
"DON'T LET ANYONE STEAL YOUR DREAM!"
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Master | Next Rank: 500 Posts
Posts: 247
Joined: Sun Jul 27, 2008 1:39 am
Thanked: 2 times
GMAT Score:660

by orel » Mon Nov 24, 2008 12:25 am
now it makes sense to me!

thanks guys!
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Senior | Next Rank: 100 Posts
Posts: 51
Joined: Wed Oct 08, 2008 12:50 pm

by GMATCHPOINT » Mon Nov 24, 2008 1:21 pm
Logitech,
If one day you decide to share your flashcards, I would love to hv a copy. hehehe.
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Post new topic Post Reply
• Page 1 of 1