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apples and oranges removed

by enriqueta26 » Sat Jul 17, 2010 9:37 am
Could someone explain this problem, please?

The contents of a box shows as following: 14 apples and 23 oranges.

How many oranges must be removed from the box to have as a result 70% of the pieces of fruit = apples?

Source Gmat practice test

[spoiler]A: 17[/spoiler]
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by singhpreet1 » Sat Jul 17, 2010 9:44 am
enriqueta26 wrote:Could someone explain this problem, please?

The contents of a box shows as following: 14 apples and 23 oranges.

How many oranges must be removed from the box to have as a result 70% of the pieces of fruit = apples?

Source Gmat practice test

[spoiler]A: 17[/spoiler]
ok my way to solve is:

we know that 14 apples will make 70% of the total, therefore rest of the 30%= 6, so 23-6=17 which is the number of oranges which need to removed.

hope that is helpful.

Preet
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by Patrick_GMATFix » Sat Jul 17, 2010 9:44 am
We start with 14 apples and 23 oranges, or 37 fruits total. After removing x oranges, there will be 37-x fruits left, and there will still be 14 apples left.

The number of apples should be 70% of the number of fruits left: 14/(37-x) = 70/100 >> x=17.

17oranges must be removed.
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by aloneontheedge » Sat Jul 17, 2010 9:49 am
Approach: There are 37 fruits in total.If X oranges are removed
Then 70%(37-X) = 14
X = 17.
Hope it is clear
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by kevincanspain » Sat Jul 17, 2010 9:53 am
singhpreet1 wrote:
enriqueta26 wrote:Could someone explain this problem, please?

The contents of a box shows as following: 14 apples and 23 oranges.

How many oranges must be removed from the box to have as a result 70% of the pieces of fruit = apples?

Source Gmat practice test

[spoiler]A: 17[/spoiler]
ok my way to solve is:

we know that 14 apples will make 70% of the total, therefore rest of the 30%= 6, so 23-6=17 which is the number of oranges which need to removed.

hope that is helpful.

Preet
This is great! If the total number of pieces of fruit is n, 14/n = 0.7 = 7/10= 14/20
Thus n must be 20 and there must be 6 oranges, 17 fewer than before
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by indiantiger » Sat Jul 17, 2010 10:42 am
Lets say the new pieces of fruit is x

then 70% of x = 14
=> 70x/100 = 14
=>7x/10 = 14
=> x = 20

total pieces of fruit after removing oranges = 20
now we not 14 are apple then 6 must be oranges

so we need to remove 17 oranges
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by enriqueta26 » Sat Jul 17, 2010 10:43 am
thank you so much guys!!
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by singhpreet1 » Sat Jul 17, 2010 10:27 pm
kevincanspain wrote:
singhpreet1 wrote:
enriqueta26 wrote:Could someone explain this problem, please?

The contents of a box shows as following: 14 apples and 23 oranges.

How many oranges must be removed from the box to have as a result 70% of the pieces of fruit = apples?

Source Gmat practice test

[spoiler]A: 17[/spoiler]
ok my way to solve is:

we know that 14 apples will make 70% of the total, therefore rest of the 30%= 6, so 23-6=17 which is the number of oranges which need to removed.

hope that is helpful.

Preet
This is great! If the total number of pieces of fruit is n, 14/n = 0.7 = 7/10= 14/20
Thus n must be 20 and there must be 6 oranges, 17 fewer than before
thanks Kevin..this is my first appreciation from a GMAT instructor! there is no other way i could interpret the question to be honest.

Preet
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by outreach » Sun Jul 18, 2010 1:28 am
percent qty of apples
70 14
30 x


hence x=(14*30)/70=6

SO WE SHOULD HAVE 6 ORANGES TO MAKE 30% OF FRUIT HAS ORANGES

23-6=17
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