Geometry DS

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Geometry DS

by gmatruler » Mon Jul 12, 2010 4:58 am
In the figure, points P and Q lie on the circle with center O. What is the value of S?

(A) 1/2

(B) 1

(C) root(2)

(D) root(3)

(E) root(2)/2


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by Patrick_GMATFix » Mon Jul 12, 2010 5:05 am
This one is very tough, but tests whether you realize that:

1) OP = OQ. and
2) If you drew a line straight down from P to the x-axis, you would form a triangle of base 1 and height root(3), so it will be a 30-60-90 triangle.

The angle measures are key because from them you can deduce a lot about s and t. it's tough to explain without drawings but the answer is B.

Have a look at a detailed solution, including a video solution: this is GMATprep question 1082. Set topic='Geometry, Coordinate' and difficulty='700+' in the drill generator to practice similar questions.

-Patrick
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by kvcpk » Mon Jul 12, 2010 5:22 am
I dont see anything attached..

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by GMATGuruNY » Mon Jul 12, 2010 6:11 am
The attached figure shows why s = 1.

Anytime you see Root3, you should think: 30-60-90 triangle.

Hope this helps!
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BTG geometry problem.pdf
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by selango » Mon Jul 12, 2010 8:07 am
After every 90 degrees the co-ordinates will get inverted with the sign assigned according to the quadrant in which the point lies.

The co-ordinates is (-V3,1).After 90 degree it will become (1,V3)[Note it is in first quadrant,so both x and y are positive]
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by Patrick_GMATFix » Mon Jul 12, 2010 8:15 am
Nice tip Selango. Thank you
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by gmatruler » Sun Jul 18, 2010 6:25 am
Patrick_GMATFix wrote:Have a look at a detailed solution, including a video solution: this is GMATprep question 1082. Set topic='Geometry, Coordinate' and difficulty='700+' in the drill generator to practice similar questions.

-Patrick
Video solution is very helpful!

Thank you guys for your help