rlovely wrote:Could someone explain the fault in the following logic (and I'm sure I'm missing something extraordinarily simple-- be gentle, this is my first post):
X takes 12 hours to complete 2/3 of task Z
At that rate of work, X would take 18 hours to complete the entire task [12*3/2]
6 hours of work remain for Y
Y works at 1/10 the speed of X
10*6 = 60
60 hours of work remain
vittalgmat wrote:X takes 12 hrs to finish his work...
At that rate he finished 2/3 of the work. So remainig work is 1/3.
Y's rate is 1/10th of X. ie. Y takes 10 times longer to finish his work.
==> 120 hrs
At the of 120 hrs how long will he take to finish 1/3 of the work ?
= 120/3 = 40 hrs.
HT helps
ankit1383 wrote:40 hours
Let Total work: 120 units
Speed of X: 10 units(since his rate is 12 hours to complete the work)
Speed of Y : 1 units per hour(1/10 of X)
Work Finished by X= 120*2/3=80
Work Left= 120-80=40
Tim taken by Y
40/1= 40 hours
Hello when I did the problem, I actually took 2/3 of the total for X and divided it by 12. To get the rate, because the question states X only got 2/3rd work done. ( picked 36 as my total) and as a result I got that it takes Y 60 hours to complete the job. Can you please explain to me why we would receive X's rate from the total and not from 2/3rd.
Thank you in advance I am hoping this explanation will help me alot.
RB
This is a dofferent method....
HTH
since x takes 2/3 of the work, then Y takes 1/3 (=1-2/3) of the work.apoorva.srivastva wrote:Working, independently X takes 12 hours to finish a certain work. he finishes 2/3 of the work . The rest of the work is finished by Y whose rate is 1/10 th of X. In how much time does Y finsh his work?
i DONT HAVE THE OA FOR THIS
