Q Each digit in the two digit number G is halved to form a new two digit number H.which of the following could be sum of G and H.
a)153 b)150 c)137 d)129 e)89
a)153 b)150 c)137 d)129 e)89
Algebraic method:quantskillsgmat wrote:Q Each digit in the two digit number G is halved to form a new two digit number H.which of the following could be sum of G and H.
a)153 b)150 c)137 d)129 e)89
Let G = 10x + y
H = (10x/2) + (y/2)
Then G + H = (10x + y) + (10x + y)/2
= (10x + y)[1 + 1/2]
= 3(10x + y)/2
= 3G/2, which implies that G + H must be a multiple of 3. Also G should be an even integer.
Since G is a 2-digit number, so if we take the maximum value of G as 98 and maximum value of H as 49 approx, then G + H = 147. So, answer choices A and B are not the possible answers.
So, from the answer choices, C, D, and E, only 129 is a multiple of 3.
The correct answer is D.
