Average Problem

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Average Problem

by akpareek » Fri Jul 30, 2010 5:14 am
Each of the 30 boxes in a certain shipment weighs either 10 pounds or 20 pounds, and
average (arithmetic mean) weight of the boxes in the shipment is 18 pounds. If the
average weight of the boxes in the shipment is to be reduced to 14 pounds by removing
some of the 20-pound boxes, how many 20-pound boxes must be removed?
A. 4
B. 6
C. 10
D. 20
E. 24
Source: — Problem Solving |

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by selango » Fri Jul 30, 2010 5:33 am
Always pl format the question properly.

Each of the 30 boxes in a certain shipment weighs either 10 pounds or 20 pounds, and average (arithmetic mean) weight of the boxes in the shipment is 18 pounds. If the average weight of the boxes in the shipment is to be reduced to 14 pounds by removing some of the 20-pound boxes, how many 20-pound boxes must be removed?
A. 4
B. 6
C. 10
D. 20
E. 24
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by selango » Fri Jul 30, 2010 5:36 am
Let w be the weight of each box..w=10 or 20 pounds

Sum/30=18 pounds

Sum=540 pounds

(Sum-20x)/(30-x)=14

Sum-20x=420-14x

540-420=6x

6x=120

x=20

Twenty 20-pound boxes are removed.

Pick D
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by GMATGuruNY » Fri Jul 30, 2010 1:17 pm
akpareek wrote:Each of the 30 boxes in a certain shipment weighs either 10 pounds or 20 pounds, and
average (arithmetic mean) weight of the boxes in the shipment is 18 pounds. If the
average weight of the boxes in the shipment is to be reduced to 14 pounds by removing
some of the 20-pound boxes, how many 20-pound boxes must be removed?
A. 4
B. 6
C. 10
D. 20
E. 24
This is a great question for plugging in the answer choices, which represent the number of 20-pound boxes that need to be removed.

Current total weight = 30*18 = 540.

Answer choice C: 10 20-pound boxes removed.
New total weight = 540 - 10*20 = 340.
New number of boxes = 30-10 = 20.
New average = 340/20 = 17.
The average is too high, so we need to remove more boxes.
Eliminate A, B and C.

Answer choice D: 20 20-pound boxes removed.
New total weight = 540 - 20*20 = 140.
New number of boxes = 30-20 = 10.
New average = 140/10 = 14. Success!

The correct answer is D.
Last edited by GMATGuruNY on Wed Sep 28, 2011 4:02 am, edited 2 times in total.
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by rsnaren » Sat Jul 31, 2010 1:50 am
GMATGuruNY wrote:
akpareek wrote:Each of the 30 boxes in a certain shipment weighs either 10 pounds or 20 pounds, and
average (arithmetic mean) weight of the boxes in the shipment is 18 pounds. If the
average weight of the boxes in the shipment is to be reduced to 14 pounds by removing
some of the 20-pound boxes, how many 20-pound boxes must be removed?
A. 4
B. 6
C. 10
D. 20
E. 24
This is a great question for plugging in the answer choices, which represent the number of 20-pound boxes that need to be removed.

Total current weight = 30*18=540.

Answer choice C:
New total weight = 540 - 10*20 = 340.
New number of boxes = 30-10 = 20.
New average = 340/20 = 17.
Need to remove more boxes.

Answer choice D:
New total weight = 540 - 20*20 = 140.
New number of boxes = 30-20 = 10.
New average = 140/10 = 14. Success!

The correct answer is D.
At Stuart: Your explanation is simply the Great for plugging in values!!!
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by dinesh19aug » Sat Jul 31, 2010 2:09 pm
If you want to solve this question using simple algebra:

Let x = no. of 10 pound box
Let y = no of 20 pound box
Let n = number of 20 pound boxes removed

Current weight:

10 X + 20y = 30 * 18 ---- eq 1

New weight :
10X + 20 (Y-n) = (30-n) *14
10x + 20 y - 20 n = 30 * 14 - 14n
10x + 20y = 6n - 30 *14 ----- eq2

Replace 10x + 20y with 30 *18
30 * 18 = 30 *14 - 6n
30*18 - 30*14 = 6n
30(18-14) = 6n
30 * 4 /6 = n
n = 20 Answer D


Dinesh