There are 15 children going to a movie. tickets cost 5

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swerve: Legendary Member; Posts: 2579; Joined: Sun Oct 29, 2017 2:04 pmFollowed by: 6 members

by swerve » Tue Jun 05, 2018 5:53 am

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There are 15 children going to a movie. Tickets cost 5 dollars each, popcorn costs $3 per serving, and candy costs $2.50 per serving. If each child gets one snack, popcorn or candy, and $21 are spent for popcorn, what is the average (arithmetic mean) cost of the trip per child to the nearest cent?

A. $2.73
B. $3.86
C. $5.96
D. $7.70
E. $7.73

The OA is E.

$21 for popcorn = 21/3 = 7 servings of popcorn
i.e. remaining 8 children got one candy each = 8*2.5 = $20

Ticket cost = 15*5 = $75
Average cost = total cost / total children = (75+21+20)/15 = $7.73.

Has anyone another strategic approach to solve this PS question? Regards!

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Source: Beat The GMAT — Problem Solving | Tue Jun 05, 2018 5:53 am

deloitte247: Legendary Member; Posts: 2214; Joined: Fri Mar 02, 2018 2:22 pmFollowed by: 5 members

by deloitte247 » Sat Jul 28, 2018 1:47 pm

Total number of children = 15
Spending on popcorn = $21
Cost of popcorn = $3 per serve.
$$Total\ serving\ =\ \frac{21}{3}=\ 7$$
Each child had either popcorn or candy
Therefore, Children had candy = 15-7 = 8
Total spending on candy = 2.5 * 8 = $20
Total spending on snacks = 20 + 21 = $41
$$Average\ spending\ on\ snacks\ =\ \frac{41}{15}=\ \text{2.733}$$
Average spending on Ticket + Snacks = $(5 + 2.733)
= $7.733
Final answer is option E.

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Scott@TargetTestPrep: GMAT Instructor; Posts: 8211; Joined: Sat Apr 25, 2015 10:56 amFollowed by: 29 members; Location: Los Angeles, CA; Thanked: 43 times

by Scott@TargetTestPrep » Wed Aug 01, 2018 3:39 pm

swerve wrote:There are 15 children going to a movie. Tickets cost 5 dollars each, popcorn costs $3 per serving, and candy costs $2.50 per serving. If each child gets one snack, popcorn or candy, and $21 are spent for popcorn, what is the average (arithmetic mean) cost of the trip per child to the nearest cent?

A. $2.73
B. $3.86
C. $5.96
D. $7.70
E. $7.73

We are given that 15 children are going to a movie and that tickets costs $5 each, popcorn costs $3 per serving, and candy costs $2.50 per serving. Each child gets 1 snack, and $21 is spent on popcorn. We need to determine the average cost per child for the trip.

Since 21 dollars is spent on popcorn, 21/3 = 7 children purchased popcorn. Thus, the other 8 children purchased candy, which means 8 x 2.5 = $20 was spent on candy. We also know that 15 x 5 = $75 dollars was spent on tickets. Let's now determine the average amount of money spent per child:

(21 + 20 + 75)/15 = 116/15 â‰ˆ $7.73

Answer: E

Scott Woodbury-Stewart
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