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E
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If n^m leaves a remainder of 1 after division by 7 for all positive integers n that are not multiples of 7, then m could be equal to:
A. 2
B. 3
C. 4
D. 5
E. 6
The OA is E.
I solved this PS question like this, as 7 is a prime number and n can only take values which are not multiples of 7 so, n and 7 will be coprime hence as per Fermat little theorem value of m will be 7 - 1 = 6 for any value of n which are not multiples of n.
Can someone explain another way to solve this PS question? Thanks!
A. 2
B. 3
C. 4
D. 5
E. 6
The OA is E.
I solved this PS question like this, as 7 is a prime number and n can only take values which are not multiples of 7 so, n and 7 will be coprime hence as per Fermat little theorem value of m will be 7 - 1 = 6 for any value of n which are not multiples of n.
Can someone explain another way to solve this PS question? Thanks!













