mehrasa wrote:Is the product abcd even?
1.a^2+b^2+c^2+d^2=0
2. a = b = c = d
[spoiler]OA: A[/spoiler]
but to me the answer is D
stat 2 is sufficient, bcuz it says all numbers are equal
if they r even product is even
if then are all odd, since all are equal it is like 4*X which will be even
what do u think?
Statement 1: a² + b² + c² + d² = 0.
Since the square of a number can never be negative, the only way to satisfy statement 1 is if a=b=c=d=0.
Thus, abcd = 0, which is even.
SUFFICIENT.
Statement 2: a=b=c=d.
If a=b=c=d=0, then abcd= 0*0*0*0 = 0, which is even.
If a=b=c=d=1, then abcd= 1*1*1*1 = 1, which is not even.
INSUFFICIENT.
The correct answer is
A.
The following statement is incorrect:
if then are all odd, since all are equal it is like 4*X which will be even.
a=b=c=d means that abcd = a*a*a*a = a�.
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