For any positive integer \(n,\) the sum of the first \(n\) positive integers equals \(\dfrac{n(n+1)}2.\) What is the sum

This topic has expert replies
Legendary Member
Posts: 2276
Joined: Sat Oct 14, 2017 6:10 am
Followed by:3 members

Timer

00:00

Your Answer

A

B

C

D

E

Global Stats

For any positive integer \(n,\) the sum of the first \(n\) positive integers equals \(\dfrac{n(n+1)}2.\) What is the sum of all the even integers between 99 and 301?

A. 10,100
B. 20,200
C. 22,650
D. 40,200
E. 45,150

[spoiler]OA=B[/spoiler]

Source: Official Guide
Source: — Problem Solving |