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coolgirl26
- Senior | Next Rank: 100 Posts
- Posts: 71
- Joined: Tue Mar 03, 2009 1:24 pm
Let S contain five numbers
s = (a,b,c,d,e)
now
I) product of all numbers = -ve
this is possible if
any one is - ve
any 3 are -ve
If one is -ve, so no. of negative(1) < no. of +ve(4)
if 3 are -ve then no. of -ve (3)> no.of+ve(2)
However in our assumption,we assumed that S contains 5 numbers, in case S contains 6
so,if no. of -ve = 3, no. of -ve = no of +ve
so we cannot precisely say anything from
(I)
(II) not suff
combine I and II
Even if there are 6 no. in the set and we know their product is -ve, we cannot say precisely that whether
1 no is -ve,2 no's are -ve or 3 no's are -ve
in case 3 no's are -ve, no of -ve = no of +ve
however in other two cases,
no. of -ve<no of +ve
Hence combining both also Insuff!!
So E
Hope this helps
Karan
