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by thephoenix » Thu Mar 25, 2010 2:29 am
duongthang wrote:integer a and n is greater than 1, the product of first 8 integers is multiple of a^n,

what is value of a

1, a^n=64

2, n=6
is the ans C
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by sanju09 » Thu Mar 25, 2010 5:02 am
duongthang wrote:integer a and n is greater than 1, the product of first 8 integers is multiple of a^n,

what is value of a

1, a^n=64

2, n=6
I think this is already discussed here, can't find the link though

I remember it read "the product of first 8 positive integers is multiple of a^n", if it's so, then we can safely assume

8! = k*a^n, where k is a positive integer

(1) If a^n = 64, with both a and n as integers greater than 1, a can take values like 2, 4, and 8; insufficient

(2) If n = 6, then 8! = k*a^6, and there's only one integer greater than 1, which has 6 or more appearances in the 8!, and that's [spoiler]2[/spoiler]; [spoiler]sufficient[/spoiler]

[spoiler]B[/spoiler]
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