How to solve this?

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by theCodeToGMAT » Mon Nov 18, 2013 5:24 am
3 + 3 + 3 + 2 X 3^2 + 2 X 3^3 + 2 X 3^4 + 2 X 3^5 + 2 X 3^6 + 2 X 3^7

3 + 2 x 3^1 + 2 X 3^2 + 2 X 3^3 + 2 X 3^4 + 2 X 3^5 + 2 X 3^6 + 2 X 3^7

3 + 2 ( 3^1 + 3^2 .. 3^7)

3 + 2 ( (3)(3^7 - 1)/(2) ) [using GP formula = a(r^n - 1)/(r-1)]

3 + 2 (3^8 - 3)/2

3 + 3^8 -3

3^8

Answer [spoiler]{B}[/spoiler]
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by Mathsbuddy » Mon Nov 18, 2013 7:53 am
A quick method:

3 + 3 + 3 + 2 X 3^2 + 2 X 3^3 + 2 X 3^4 + 2 X 3^5 + 2 X 3^6 + 2 X 3^7 =

This is the sum of these terms

1 * 3^1
plus these
2 * 3^1
2 * 3^2
2 * 3^3
2 * 3^4
2 * 3^5
2 * 3^6
2 * 3^7

In base 3, this equals 10 + 22222220 = 30000000

which in our base 10 equals 3^8

(Only for those who understand bases)

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by GMATGuruNY » Mon Nov 18, 2013 8:47 am
3 + 3 + 3 + 2 × 3^2 + 2 × 3^3 + 2 × 3^4 + 2 × 3^5 + 2 × 3^6 + 2 × 3^7 =

A. 3^7
B. 3^8
C. 3^14
D. 3^28
E. 3^30
Always look at the answer choices BEFORE you start to work.
Here, the answer choices are SPREAD OUT.
Thus, we can quickly BALLPARK the correct answer.
Since the greatest term = 2 * 3�, the sum of ALL the terms must be GREATER than 3�.
Eliminate A.

2 * 3� = 2 * 3³ * 3� = 2 * 27 * 81 ≈ 60*80 = 4800.
2 * 3� = (2 * 3�)/3 = 4800/3 = 1600.
2 * 3� = (2 * 3�)/3 ≈ 1600/3 ≈ 500.
The terms to the left of 2 * 3� will be relatively small and thus will have little effect on the final sum.
For example, 2 * 3� = 2*81 = 162, which is very small relative to the other values (4800, 1600, and 500).
Thus, we can ignore the remaining terms when we approximate the sum, implying that the correct answer ≈ 4800+1600+500 = 7000.

Look at the remaining answer choices.
C: 3¹� = 3� * 3� * 3� * 3² = 81*81*81*9 ≈ 80*80*80*10.
Thus, answer choices C, D and E are WAY too big.

The correct answer is B.
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