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Divisible by both 3 and 4

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Divisible by both 3 and 4

by rahulvsd » Fri May 04, 2012 6:34 am
How many positive three-digit integers are divisible by both 3 and 4?

A. 75
B. 128
C. 150
D. 225
E. 300
[spoiler]
OA: 75. I solved this by the following way.
Smallest 3 digit number: 100
Biggest 3 digit number: 999
Total number of 3 digit numbers: 999-100 + 1= 900
Total number of integers divisible by 12 = 900/12 = 75.
Can you confirm if this method is correct? [/spoiler]
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by mathbyvemuri » Fri May 04, 2012 9:26 am
yes it's a perfect way of doing. You can verify it like this:
3-digit multiples of 12 starts with 108 (12*9) and ends with 996 (12*83)
ie., 83-9+1 = 75 numbers
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