Whenever comparison of powers of any variable is involved, always try to follow the steps as applicable... (move to the next step only if you can't found a contradiction in previous step)sivanhas wrote:D is not equal to 0. Is D > 0?
i. D is the median of D, 1/D, -D
ii. D^3 is the median of D, D^2, D^3
- #1. Plug 1 and -1 and check.
#2. If the variable is positive, plug values greater than 1 as well as less than 1.
#3. If the variable is negative, plug values less than -1 as well as greater than -1.
- D = 1 ---> median of 1, 1/1, and -1 is 1 ---> median of 1, 1², and 1³ is 1³
D = -1 ---> median of -1, -1/1, and -(-1) is -1 ---> median of -1, (-1)², and (-1)³ is (-1³)
The correct answer is E.
