BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Help PlZzzz

This topic has expert replies
Post new topic Post Reply
Previous Topic Next Topic
Junior | Next Rank: 30 Posts
Posts: 17
Joined: Thu Jul 22, 2010 3:15 pm

Help PlZzzz

by Pinku » Thu Jul 22, 2010 10:01 pm
Given that in a pack of plates, 1/3 plates are damaged, 2/3 plates are cracked and 1/3 of them are damaged and cracked. If 80 are not hampered, then what is the number of total plates?
Top
Source: — Problem Solving |
Senior | Next Rank: 100 Posts
Posts: 95
Joined: Tue Jun 08, 2010 11:27 am
Thanked: 7 times

by singhpreet1 » Thu Jul 22, 2010 10:10 pm
Pinku wrote:Given that in a pack of plates, 1/3 plates are damaged, 2/3 plates are cracked and 1/3 of them are damaged and cracked. If 80 are not hampered, then what is the number of total plates?
1/3 are damaged, 2/3 are cracked , but only 1/3 are cracked and damaged, therefore 1/3 are still left which is given as 80, therefore, 1/3 is 80, total is 3*80= 240

Preet
Top
User avatar
Legendary Member
Posts: 748
Joined: Sun Jan 31, 2010 7:54 am
Thanked: 46 times
Followed by:3 members

by outreach » Thu Jul 22, 2010 11:43 pm
A - cracked plate
B - damaged plate


Total no plates that are cracked and damaged(A U B)=
Total A + total B - total in A&B
=1/3+2/3-1/3
=2/3


plates that are not hampered = 1 -2/3=1/3

given

1/3=80
1 = T

T =80*3=240
-------------------------------------
--------------------------------------
General blog
https://amarnaik.wordpress.com
MBA blog
https://amarrnaik.blocked/
Top
Post new topic Post Reply
• Page 1 of 1