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Mixtures problem

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by Chaitanya_1986 » Mon May 02, 2011 11:44 am
If 12 ounces of a strong vinegar solution are diluted with 50 ounces of water to form a three-percent vinegar solution, what was the concentration of the original solution?
19.3%
17%
16.67%
15.5%
12.5%

OA is D)
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by GMATGuruNY » Mon May 02, 2011 12:34 pm
Chaitanya_1986 wrote:If 12 ounces of a strong vinegar solution are diluted with 50 ounces of water to form a three-percent vinegar solution, what was the concentration of the original solution?
19.3%
17%
16.67%
15.5%
12.5%

OA is D)
Volume of mixture = solution+water = 12+50 = 62 ounces.
Amount of vinegar in mixture = (.03)*62 = 1.86 ounces.
Percentage of vinegar in original solution = (1.86)/12 * 100 = 15.5.

The correct answer is D.
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by smackmartine » Mon May 02, 2011 7:30 pm
Please use spoiler to mask the OA so that everyone can take unbiased attempt to solve the problem.
Chaitanya_1986 wrote:If 12 ounces of a strong vinegar solution are diluted with 50 ounces of water to form a three-percent vinegar solution, what was the concentration of the original solution?
19.3%
17%
16.67%
15.5%
12.5%

OA is D)
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by Chaitanya_1986 » Mon May 02, 2011 10:27 pm
Thanks Mitch for your explanation
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