Chaitanya_1986 wrote:If 12 ounces of a strong vinegar solution are diluted with 50 ounces of water to form a three-percent vinegar solution, what was the concentration of the original solution?
19.3%
17%
16.67%
15.5%
12.5%
OA is D)
Volume of mixture = solution+water = 12+50 = 62 ounces.
Amount of vinegar in mixture = (.03)*62 = 1.86 ounces.
Percentage of vinegar in original solution = (1.86)/12 * 100 = 15.5.
The correct answer is
D.
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