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MakeitHappen
- Junior | Next Rank: 30 Posts
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- Joined: Sun Dec 13, 2009 12:30 am
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I found the below mentioned tip for solving remainder problem from some forum(cant rem which one but i had it saved on my laptop..so i dont rem the source):
Cycle of powers : This is used to find the remainder of , when divided by 10, as it helps us in figuring out the last digit of .
The cycle of powers for numbers from 2 to 10 is given below:
2: 2, 4, 8, 6 → all will have the same last digit.
3: 3, 9, 7, 1 → all will have the same last digit.
4: 4, 6 → all will have the same last digit.
5: 5 → all will have the same last digit.
6: 6 → all will have the same last digit.
7: 7, 9, 3, 1 → all will have the same last digit.
8: 8, 4, 2, 6 → all will have the same last digit.
9: 9, 1 → all will have the same last digit.
10: 0 → all will have the same last digit.
I didnt quite understand the above!!! Any help appreciated...thanks in advance
Cycle of powers : This is used to find the remainder of , when divided by 10, as it helps us in figuring out the last digit of .
The cycle of powers for numbers from 2 to 10 is given below:
2: 2, 4, 8, 6 → all will have the same last digit.
3: 3, 9, 7, 1 → all will have the same last digit.
4: 4, 6 → all will have the same last digit.
5: 5 → all will have the same last digit.
6: 6 → all will have the same last digit.
7: 7, 9, 3, 1 → all will have the same last digit.
8: 8, 4, 2, 6 → all will have the same last digit.
9: 9, 1 → all will have the same last digit.
10: 0 → all will have the same last digit.
I didnt quite understand the above!!! Any help appreciated...thanks in advance












