C & P

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C & P

by opponent » Fri Mar 04, 2011 8:59 am
A mocktail has to be prepared from 3 kinds of whisky, 4 kinds of soda, and 5 kinds of fruit juice. How many mocktails can be made taking at least one of each other kind?
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by vineeshp » Fri Mar 04, 2011 9:56 am
Is the answer 3255? (7*15*31)
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by Anurag@Gurome » Fri Mar 04, 2011 10:52 am
opponent wrote:A mocktail has to be prepared from 3 kinds of whisky, 4 kinds of soda, and 5 kinds of fruit juice. How many mocktails can be made taking at least one of each other kind?
Number of ways to select at least one object from n different objects = (2^n - 1)

Therefore,
Number of ways we can select at least one whiskey from 3 kinds of whiskey = (2^3 - 1) = 7
Number of ways we can select at least one soda from 4 kinds of soda = (2^4 - 1) = 15
Number of ways we can select at least one fruit juice from 5 kinds of fruit juice = (2^5 - 1) = 15

Hence, total number of possible combinations = 7*15*31 = 3255
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