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official guide 13 question# 198, page 180

Expert replies
by HalifaxGuy » Tue Oct 16, 2012 1:44 am
can anyone help with this question

last sunday certain store sold copies of newspaper A for $1 each and copies of newspaper B for $1.25 each and the store sold no other newspapers thtat day. if r percent of the stores revenue from newspaper sales was from nespaper A and if p percent of newspapers that the store sold were copies of newspaper A, which of the follwoing expresses r interms of p?

correct answer is 400p/500-p

how?
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Source: — Problem Solving |

by anuprajan5 » Tue Oct 16, 2012 2:22 am
I would solve this through plugging in numbers and then checking my answer choices.

Assume 1 newspaper A was sold and 4 newspaper Bs were sold

Therfore 1*1$$ + 4*1.25$ = 6$

Therefore A's revenue percentage ie; r = (1/6)*100 = 16,67%
A's copy percentage ie; p = (1/5)*100 = 20%

The answer choice, if you plug in the numbers you will find that r = 400p/(500-p) = 8000/480 = 16,67%

Regards
Anup
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by GMATGuruNY » Tue Oct 16, 2012 3:05 am
Last Sunday a certain store sold copies of Newspaper A for $1 and Newspaper B for 1.25. If r percent of the stores revenue came from newspaper sales of Paper A and if p percent of the newspapers sold that day were A, which of the following expresses r in terms of p?

100p/125-p
150p/250-p
300p/375-p
400p/500-p
500p/625-p
Plug in numbers that make the math easy.

If the number of copies of A = the number of copies of B, then p=50, since 1/2 of the newspapers sold are A.

If 4 copies of each type of newspaper are sold, then the total revenue will be an integer:
Revenue from 4 copies of A = 4*1 = 4.
Revenue from 4 copies of B = 4*1.25 = 5.
Total revenue = 4+5 = 9.

Since r% of the revenue comes from A:
r = revenue from A/total revenue * 100 = 4/9 * 100 = 400/9. This is our target.

Now we plug p=50 into the answers to see which yields our target of 400/9.
The denominator of the correct answer choice must yield a multiple of 9.
For an integer to be a multiple of 9, the sum of its digits must be a multiple of 9.
A quick scan of the denominators reveals that only D works:

125-p = 125-50 = 75. Not a multiple of 9.
250-p = 250-50 = 200. Not a multiple of 9.
375-p = 375-50 = 325. Not a multiple of 9.
500-p = 500-50 = 450, which is a multiple of 9.
625-p = 625-50 = 575. Not a multiple of 9.

The correct answer is D.
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by mcdesty » Wed Jul 02, 2014 9:20 am
See Image Below.
Come up with your own example and solve the same problem at least twice if you got this wrong or took more that 1 minute and 45 seconds to solve this.
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by Brent@GMATPrepNow » Wed Jul 02, 2014 10:35 am
Last Sunday a certain store sold copies of Newspaper A for $1.00 each and copies of Newspaper B for $1.25 each, and the store sold no other newspapers that day. If r percent of the store's revenues from newspaper sales was from Newspaper A and if p percent of the newspapers that the store sold were copies of newspaper A, which of the following expresses r in terms of p?

A. 100p/(125 - p)
B. 150p/(250 - p)
C. 300p/(375 - p)
D. 400p/(500 - p)
E. 500p/(625 - p)
If you're not sure how to proceed with this question, or if you're behind on time and you want to catch up, you can give yourself a 50-50 chance in about 10 seconds.

To do so, we'll see what happens when we use an EXTREME value for p.
Say p = 100
In other words, 100% of the newspapers sold were Newspaper A.
This means that 100% of the revenue is from Newspaper A.
In other words, when p = 100, then r = 100

At this point, we'll plug in 100 for p and see which one yields a value of 100.
Only answer choices B and D work.
B) 150(100)/(250-100) = 100 PERFECT
D) 400(100)/(500-100) = 100 PERFECT

Make your guess (B or D) and move on.

Cheers,
Brent
Brent Hanneson - Creator of GMATPrepNow.com
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by ceilidh.erickson » Fri Jul 04, 2014 9:47 am
This is one of the hardest questions in OG13, and one that most students should not attempt! Even students aiming for a 750 would be well advised to guess on a question like this. None of the solution paths (picking #s or algebra) is likely to get you there in under 3 min, and stubborn students could get bogged down for 4 or 5 minutes. Other experts have provided good solutions, but remember - your goal is not to get every single question correct! Your goal is to maximize the getable ones in the given time window.

A savvy test-taker would do as Brent suggested: pick the easiest numbers possible (100 and 0), and then have a 50/50 chance of guessing the right answer in 30 seconds.
Ceilidh Erickson
EdM in Mind, Brain, and Education
Harvard Graduate School of Education
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