Source- Veritas
What is the probability of getting exactly 2 sixes on three rolls of a fair six sided side?
Please verify my solution.
[spoiler]Possible Scenario 1 - Roll 1 - 6 ; Roll 2 - 6 ; Roll 3 - X (a number other than 6)
P(6) AND P(6) AND P (NOT 6)
1/6 * 1/6 * 5/6 = 5/216
No of ways to rearrange possible scenario 1 - Permutations with duplicates
3!/2! = 3
Therefore, 15/216[/spoiler]
What is the probability of getting exactly 2 sixes on three rolls of a fair six sided side?
Please verify my solution.
[spoiler]Possible Scenario 1 - Roll 1 - 6 ; Roll 2 - 6 ; Roll 3 - X (a number other than 6)
P(6) AND P(6) AND P (NOT 6)
1/6 * 1/6 * 5/6 = 5/216
No of ways to rearrange possible scenario 1 - Permutations with duplicates
3!/2! = 3
Therefore, 15/216[/spoiler]
