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A market research firm surveyed 400 citizens of city A amd 6

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A market research firm surveyed 400 citizens of city A amd 6

by alanforde800Maximus » Sun Oct 16, 2016 1:43 am
A market research firm surveyed 400 citizens of city A and 600 citizens of city B during a consumer preference study for a new beverage. If 63% of the citizens surveyed from city A and 48% of the citizens surveyed from city B indicated that they enjoyed the new beverage, what %age of the total number of citizens surveyed enjoyed the new beverage?

a) 45
b) 48
c) 54
d) 56
e) 63

Please assist with above problem.
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by melguy » Sun Oct 16, 2016 2:54 am
Using this method you can calculate percentage very quickly (Credit Brent @ GMAT Prep : https://www.gmatprepnow.com)
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by GMATGuruNY » Sun Oct 16, 2016 3:39 am
The problem above is the same as the following:
A is 63% alcohol.
B is 48% alcohol.
If 400 liters of A are mixed with 600 liters of B, what percentage of the resulting mixture will be alcohol?
(total amount of A)/(total amount of B) = 400/600 = 2/3.
Implication:
Every 2 liters of A's 63% alcohol solution is mixed with 3 liters of B's 48% alcohol solution.
Thus:
Average percentage of alcohol per every 5 liters = (2*63 + 3*48)/5 = 270/5 = 54.

The correct answer is C.
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by fiza gupta » Sun Oct 16, 2016 5:42 am
Number of Citizens who enjoyed new Beverages:
from citizen A : 63/100*400 = 252
from citizen B : 48/100*600 = 288
total = 1000
% ((252+288)/1000)*100
= 54%
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