gmatapril wrote:Given the ascending set of positive integers {a, b, c, d, e, f}, is the median greater than the mean?
(1) a + e = (3/4)(c + d)
(2) b + f = (4/3)(c + d)
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- ankur.agrawal
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[spoiler]IMO 'C'[/spoiler]
can you please explain your answer
ankur.agrawal wrote:[spoiler]IMO 'C'[/spoiler]
gmatapril wrote:Given the ascending set of positive integers {a, b, c, d, e, f}, is the median greater than the mean?
(1) a + e = (3/4)(c + d)
(2) b + f = (4/3)(c + d)
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Median = (c+d)/2gmatapril wrote:Given the ascending set of positive integers {a, b, c, d, e, f}, is the median greater than the mean?
(1) a + e = (3/4)(c + d)
(2) b + f = (4/3)(c + d)
Average = (a+b+c+d+e+f)/6
Median > Average
(c+d)/2 > (a+b+c+d+e+f)/6
3c + 3d > a+b+c+d+e+f
2c + 2d > a+b+e+f
2(c+d) > a+b+e+f
Thus, the question can be rephrased:
Is 2(c+d) > a+b+e+f?
Statement 1: a + e = (3/4)(c + d)
No information about b+f.
Insufficient.
Statement 2: b + f = (4/3)(c + d)
No information about a+e.
Insufficient.
Statement 1 and 2 together:
Adding the equations, we get:
a+b+e+f = (3/4)(c+d) + (4/3)(c+d)
a+b+e+f = (3/4 + 4/3)(c+d)
a+b+e+f = (25/12)(c+d)
Sufficient.
The correct answer is C.
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Followed here and elsewhere by over 1900 test-takers.
I have worked with students based in the US, Australia, Taiwan, China, Tajikistan, Kuwait, Saudi Arabia -- a long list of countries.
My students have been admitted to HBS, CBS, Tuck, Yale, Stern, Fuqua -- a long list of top programs.
As a tutor, I don't simply teach you how I would approach problems.
I unlock the best way for YOU to solve problems.
For more information, please email me (Mitch Hunt) at [email protected].
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