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sequences

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by resilient » Wed Apr 09, 2008 5:39 pm
If S is the infinite sequence S1 = 6, S2 = 12, ..., Sn = Sn-1 + 6,..., what is the sum of all terms in the set {S13, S14, ..., S28}?



1,800
1,845
1,890
1,968
2,016


I am having troubles trying to understand these types of questions. I am wondering if anyone can show me where to go to learn ALL about this topic. I almost always get snagged by this and would liek to master it!


qa is D
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Source: — Problem Solving |

by Neo2000 » Wed Apr 09, 2008 9:48 pm
You will notice that your series is 6,12,18,....

which means Sn = 6xn

So S13 = 6x13
And S28 = 6x28

As you are adding them (6x13)+(6x14)+....(6x28)
Taking 6 common 6x (13+14+15+...28 )

At this point you can either

a)list and add all the numbers
b) notice that you have 13+14+15+...25+26+27+28 = 40(x7) + 20+ 28
c) Find the (sum of first 28 numbers - Sum of first 12numbers) and multiply by 6 to get your answer.

I did option C btw :)
Last edited by Neo2000 on Thu Apr 10, 2008 1:15 am, edited 1 time in total.
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Re: sequences

by lunarpower » Thu Apr 10, 2008 12:54 am
Enginpasa1 wrote:If S is the infinite sequence S1 = 6, S2 = 12, ..., Sn = Sn-1 + 6,..., what is the sum of all terms in the set {S13, S14, ..., S28}?



1,800
1,845
1,890
1,968
2,016


I am having troubles trying to understand these types of questions. I am wondering if anyone can show me where to go to learn ALL about this topic. I almost always get snagged by this and would liek to master it!


qa is D
the whole Sn Sn-1 thing is just there to scare you; in fact, these sequences (called recursive sequences) are actually EASIER to understand than 'traditional' sequences defined by a formula. here's why:

'Sn' can be thought of as just 'the current term', or 'the term i'm thinking about right now'
'Sn-1' can be thought of as 'the previous term', or 'the term immediately before the one i'm thinking about right now'

so ...
you can read the given formula as, 'to get any term of the sequence, you add 6 to the previous term'. that's easy to think about.

alternatively, you can just look at the terms they give you and extract the pattern; even if you don't understand the formula right away, the odds are good that you'll be able to see the pattern by looking at the numbers.

--

these sequences don't usually have a separate chapter in anyone's math book because they're arithmetic sequences; they follow the same rules as sequences of consecutive integers, consecutive odds, or consecutive evens, which are really jsut special cases of arithmetic sequences. namely, they follow these rules:
* the average (arithmetic mean) of all the numbers in the sequence is the same as the median of the sequence
* the sum of all the terms in the sequence can be calculated as (number of terms) x (median), a fact that follows from the fact above
* the sum of all the terms can also be calculated as (1/2) x (number of terms) x (sum of first + last terms)

that's probably about all you have to know about these sequences. remember, all these facts work for sequences of consecutive odds, consecutive evens, and consecutive integers.
Ron has been teaching various standardized tests for 20 years.

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by xilef » Thu Apr 10, 2008 3:55 pm
[16*(78+168)]/2=1968
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by YARAB800 » Sat Jan 16, 2010 11:35 am
xilef wrote:[16*(78+168)]/2=1968
I don't understand how you came up with 16? shouldn't it be 15??

**Sum of all term = 1\2 number of terms * ( sum of first + last terms)

shouldn't the sum of terms be 28-13 = 15?
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by viidyasagar » Sat Feb 13, 2010 6:55 am
shouldn't the sum of terms be 28-13 = 15?
13, 14, 15, 16......17, 18, 19, 20......21, 22, 23, 24.....25, 26, 27, 28 - no of terms = 16 terms, not the sum

Remember as thumb rule..when we have to count both the first and the last term of any set of consecutive numbers, then do the traditional subtraction and add 1.

hence 28 - 13 = 15 and then add 1 = 16
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by komal » Tue Feb 16, 2010 9:05 am
If S is the infinite sequence S1 = 6, S2 = 12, ..., Sn = Sn-1 + 6,..., what is the sum of all terms in the set {S13, S14, ..., S28}?

1,800
1,845
1,890
1,968
2,016

I am having troubles trying to understand these types of questions. I am wondering if anyone can show me where to go to learn ALL about this topic. I almost always get snagged by this and would liek to master it!

sum = s13 + s14 + ................+ s28
sum = 6x13 + 6x14 + .................. + 6x28
sum = 6 (13 + 14 + 28)
sum = 6 [16 x (13 + 28)/2]
sum = 6 [8 x (41)]
sum = 6 x 328
sum = 1968
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