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It goes like this:-bhumika.k.shah wrote:A grocery store sells two varieties of jelly bean jars, and each type of jellybean jar contains only red and yellow jellybeans. If jar B contains 20% more red jellybeans than jar A , but 10% fewer yellow jellybeans, and jar A contains twice as many red jellybeans as yellow jellybeans,by what percent is the number of jellybeans in jar B larger than the number of jellybeans in jar A ?
[spoiler]source : MGMAT %
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Jar A : R, Y --> 2Y , Y total = 3Ybhumika.k.shah wrote:A grocery store sells two varieties of jelly bean jars, and each type of jellybean jar contains only red and yellow jellybeans. If jar B contains 20% more red jellybeans than jar A , but 10% fewer yellow jellybeans, and jar A contains twice as many red jellybeans as yellow jellybeans,by what percent is the number of jellybeans in jar B larger than the number of jellybeans in jar A ?
[spoiler]source : MGMAT %
[/spoiler]
Harsh I think u did a mistake here .. we have to calculate percent is the number of jellybeans in jar B larger than the number of jellybeans in jar A so the reference is A. So you should calculate it this wayharsh.champ wrote:It goes like this:-bhumika.k.shah wrote:A grocery store sells two varieties of jelly bean jars, and each type of jellybean jar contains only red and yellow jellybeans. If jar B contains 20% more red jellybeans than jar A , but 10% fewer yellow jellybeans, and jar A contains twice as many red jellybeans as yellow jellybeans,by what percent is the number of jellybeans in jar B larger than the number of jellybeans in jar A ?
[spoiler]source : MGMAT %
[/spoiler]
Let R in jar A nd B be x and y,Yellow in jar A and B be a and b.
y=1.2x =2.4a
b=0.9a
x=2a
We have to find (b+y) - (a+x)/(b+y)=3.3 -3 / 3 =1/11 = 9.09%
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