It has to be 62
say the sequence question talks about is
k is integer greater than 2
x, kx, k^2x, k^3 x, k^4 x
and k^4 x<1000
For x to be maximum, make k minimum. so k=2, since k cannot be 1 as per question.
5th term = 2^4 x, if x =62
5th term = 988 the largest possible value of 2^4 x less than 1000.
so IMO A.
sequence.
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Source: Beat The GMAT — Problem Solving |
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goyalsau
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No man the answer is 63lokesh r wrote:It has to be 62
say the sequence question talks about is
k is integer greater than 2
x, kx, k^2x, k^3 x, k^4 x
and k^4 x<1000
For x to be maximum, make k minimum. so k=2, since k cannot be 1 as per question.
5th term = 2^4 x, if x =62
5th term = 988 the largest possible value of 2^4 x less than 1000.
so IMO A.
I think they are are considering 0
As zero is a positive integer.
I don't know i am right or wrong but i only find this reason for the answer to be 63.
I m editing this post just to write down that i put in 5 minutes and 6 seconds to get the right answer and still got it wrong.
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lokesh r
- Master | Next Rank: 500 Posts
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- Joined: Sat Sep 04, 2010 2:27 am
- Location: Leeds,UK
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yes you are right..goyalsau wrote:No man the answer is 63lokesh r wrote:It has to be 62
say the sequence question talks about is
k is integer greater than 2
x, kx, k^2x, k^3 x, k^4 x
and k^4 x<1000
For x to be maximum, make k minimum. so k=2, since k cannot be 1 as per question.
5th term = 2^4 x, if x =62
5th term = 988 the largest possible value of 2^4 x less than 1000.
so IMO A.
I think they are are considering 0
As zero is a positive integer.
I don't know i am right or wrong but i only find this reason for the answer to be 63.
I m editing this post just to write down that i put in 5 minutes and 6 seconds to get the right answer and still got it wrong.
zero is neither +ve nor -ve.
so it is ( zero , 1,2,3....62) , that is 63 terms..
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goyalsau
- Legendary Member
- Posts: 866
- Joined: Mon Aug 02, 2010 6:46 pm
- Location: Gwalior, India
- Thanked: 31 times
you are saying Zero is neither +ve nor -velokesh r wrote:yes you are right..goyalsau wrote:No man the answer is 63lokesh r wrote:It has to be 62
say the sequence question talks about is
k is integer greater than 2
x, kx, k^2x, k^3 x, k^4 x
and k^4 x<1000
For x to be maximum, make k minimum. so k=2, since k cannot be 1 as per question.
5th term = 2^4 x, if x =62
5th term = 988 the largest possible value of 2^4 x less than 1000.
so IMO A.
I think they are are considering 0
As zero is a positive integer.
I don't know i am right or wrong but i only find this reason for the answer to be 63.
I m editing this post just to write down that i put in 5 minutes and 6 seconds to get the right answer and still got it wrong.
zero is neither +ve nor -ve.
so it is ( zero , 1,2,3....62) , that is 63 terms..
but as i know Zero is +ve.
Please correct me if i am wrong.
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lokesh r
- Master | Next Rank: 500 Posts
- Posts: 156
- Joined: Sat Sep 04, 2010 2:27 am
- Location: Leeds,UK
- Thanked: 1 times
Please check this below link.goyalsau wrote:you are saying Zero is neither +ve nor -velokesh r wrote:yes you are right..goyalsau wrote:No man the answer is 63lokesh r wrote:It has to be 62
say the sequence question talks about is
k is integer greater than 2
x, kx, k^2x, k^3 x, k^4 x
and k^4 x<1000
For x to be maximum, make k minimum. so k=2, since k cannot be 1 as per question.
5th term = 2^4 x, if x =62
5th term = 988 the largest possible value of 2^4 x less than 1000.
so IMO A.
I think they are are considering 0
As zero is a positive integer.
I don't know i am right or wrong but i only find this reason for the answer to be 63.
I m editing this post just to write down that i put in 5 minutes and 6 seconds to get the right answer and still got it wrong.
zero is neither +ve nor -ve.
so it is ( zero , 1,2,3....62) , that is 63 terms..
but as i know Zero is +ve.
Please correct me if i am wrong.
https://answers.yahoo.com/question/index ... 157AAyW3ZI
would be happy if any expert can comment on this.
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goyalsau
- Legendary Member
- Posts: 866
- Joined: Mon Aug 02, 2010 6:46 pm
- Location: Gwalior, India
- Thanked: 31 times
Well Lokesh I am still not clear With Zero
Because problem says all those numbers which are not negative
as per the definition of ZERO
IT is not -ve
But if it is not even positive Then how can we consider zero in the above Case then the answer must be 62.
completely Confused
Experts please comment on this..
Because problem says all those numbers which are not negative
as per the definition of ZERO
IT is not -ve
But if it is not even positive Then how can we consider zero in the above Case then the answer must be 62.
completely Confused
Experts please comment on this..
