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Algebra- quadratic equations question

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Source: — Problem Solving |

by rijul007 » Sat Feb 25, 2012 8:28 pm
HG10 wrote:If (r - 4) is a factor of r^2 - kr - 36, then k =

(a) 16
(b) 5
(c) 0
(d) - 5
(e) - 16

Answer D
This ques can be done by plugging numbers

say r = 7

3 is a factor of 49-7k-36
13-7k

now plug each value and eliminate answer choices

(A)16
13 - 112 = 99
3 is a factor of 99
Keep it

(b)5
13-35 = -22
3 is not a factor of -22
Eliminate

(c)0
13-0
3 is not a factor of 13
Eliminate

(D)-5
13+35
48
3 is a factor of 48
Keep it

(E)-16
13+112
125
3 is not a factor of 125
Eliminate


Answer choices left A and D

Now put r= 9
(9-4) is a factor of 81-9k-36
5 is a factor of 45-9k

(A)16

45-9(16) = not divisible by 5
Eliminate

Only D is left so you can mark it and move on.
or you can check, if you want to waste time
;)

Option D
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by GMATGuruNY » Sat Feb 25, 2012 9:02 pm
HG10 wrote:If (r - 4) is a factor of r^2 - kr - 36, then k =

(a) 16
(b) 5
(c) 0
(d) - 5
(e) - 16

Answer D
For each factor of a quadratic there is a ROOT: the value that makes the factor equal to 0.
Since (r-4) is a factor here, r=4 is one of the roots of the equation r² - kr - 36 = 0.
Thus, we can plug in r=4 and solve for k:
4² - k(4) - 36 = 0
-4k = 20
k = -5.

The correct answer is D.
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by Troika » Sat Feb 25, 2012 9:57 pm
@rijul and GmatGuruNY: thank you for the explanations!
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by ArunangsuSahu » Wed Feb 29, 2012 12:49 pm
Substitute r=4
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