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in 2004, 2,400 condos sold, 15% of the total housing units sold that year...

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Re: in 2004, 2,400 condos sold, 15% of the total housing units sold that year...

by Brent@GMATPrepNow » Fri Jun 12, 2020 6:12 am
BTGmoderatorLU wrote: ↑
Fri Jun 12, 2020 4:34 am
 Source: Magoosh

In 2004, 2,400 condos sold, 15% of the total housing units sold that year. How many units sold in 2004 were not condos?

A. 16,000
B. 13,600
C. 12,400
D. 11, 200
E. 8,600

The OA is B
Let n = the TOTAL number of units sold in 2004:
We can write: 15% of n = 2400
In other words 0.15n = 2400
Solve: n = 2400/0.15 = 16,000

If a total of 16,000 units were sold, and 2,400 or condos, then the number of NON condos = 16,000 - 2,400 = 13,600.

Answer: B
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Re: in 2004, 2,400 condos sold, 15% of the total housing units sold that year...

by Scott@TargetTestPrep » Wed Jun 17, 2020 3:23 am
BTGmoderatorLU wrote: ↑
Fri Jun 12, 2020 4:34 am
 Source: Magoosh

In 2004, 2,400 condos sold, 15% of the total housing units sold that year. How many units sold in 2004 were not condos?

A. 16,000
B. 13,600
C. 12,400
D. 11, 200
E. 8,600

The OA is B
Solution:

We can create the following equation in which n = the total number of housing units sold in 2004:

2,400 = 0.15n

2,400/0.15 = n

16,000 = n

Thus, the number of housing units sold that were not condos was 16,000 - 2,400 = 13,600.

Alternate Solution:

We can set up a ratio: if 15% is 2,400, then 85% is x, as follows:

0.15/2400 = 0.85/x

0.15x = 2400 * 0.85

x = (2400 * 0.85)/0.15

x = 13,600

Answer: B

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