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Standard deviation depends on deviation.

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by BTGmoderatorAT » Sun Jan 28, 2018 9:03 am
Standard deviation depends on deviation.
A. {2,2,5,8,8} => {-3,-3,0,3,3}
B. {3,4,5,6,7} => {-2-1,0,1,2}
C. {1,3,5,7,9} => {-4,-2,0,2,4}
D. {3,3,5,7,7} => {-2,-2,0,2,2}
E. {0,4,5,6,10} => {-5,-1,0,1,5}

Is there a strategic approach to this question?
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Source: — Problem Solving |

by DavidG@VeritasPrep » Sun Jan 28, 2018 11:46 am
ardz24 wrote:Standard deviation depends on deviation.
A. {2,2,5,8,8} => {-3,-3,0,3,3}
B. {3,4,5,6,7} => {-2-1,0,1,2}
C. {1,3,5,7,9} => {-4,-2,0,2,4}
D. {3,3,5,7,7} => {-2,-2,0,2,2}
E. {0,4,5,6,10} => {-5,-1,0,1,5}

Is there a strategic approach to this question?
This question seems to be lacking a... question. The concept invoked here is that if you add the same value to each element of a set, the standard deviation remains unchanged.
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