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water tank

by gmatnmein2010 » Fri Feb 19, 2010 7:58 pm
Working at a constant rate respectively, pumps X and Y took 48 hours to fill an empty water tank. What fraction of the water in a full tank came from pump X?

(1) working alone at its constant rate, pump X would have taken 80 minutes to fill tank with water

(2) working alone at its constant rate, pump y would have taken 120 minutes to fill up the tank
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Source: — Data Sufficiency |
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by thephoenix » Fri Feb 19, 2010 9:27 pm
gmatnmein2010 wrote:Working at a constant rate respectively, pumps X and Y took 48 hours to fill an empty water tank. What fraction of the water in a full tank came from pump X?

(1) working alone at its constant rate, pump X would have taken 80 minutes to fill tank with water

(2) working alone at its constant rate, pump y would have taken 120 minutes to fill up the tank

is it hrs or min.

IMO D

given x and y together take 48mins.
----->1/X + 1/Y = 1/48

stmnt1 - Pump X 80mins to fill the tank so in 48mins it will fill 48/80 * 100 = 60% of the tank. hence suff

stmnt2 - since Y takes 120mins
to fill tank then in 48mins it will fill 48/120 * 100 = 40%. the remaining 60% is filled by X. hence suff

so D
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by shashank.ism » Sat Feb 20, 2010 10:14 pm
gmatnmein2010 wrote:Working at a constant rate respectively, pumps X and Y took 48 hours to fill an empty water tank. What fraction of the water in a full tank came from pump X?

(1) working alone at its constant rate, pump X would have taken 80 minutes to fill tank with water

(2) working alone at its constant rate, pump y would have taken 120 minutes to fill up the tank
I think there is some mistake in the question...If X can fill tank in 80 minutes
or Y can fill tank in 120 min.

How can both tak 48 hours to fill the tank...sth fishy .....gmatnmein2010 please chk the question from OS
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