It's a simple one but I'm not sure what the best approach is.
If there are six numbers numbered 1-6, what is the probability of choosing numbers 1, 2, and 3?
My approach: because order doesn't matter I used the combination 6 choose 3 which equals 20 possible combinations. Then there is only one combination out of these 20 that has 1, 2, and 3 so the probability is 1/20. Is that right?
If anyone can post with an explanation that would be fantastic.
If there are six numbers numbered 1-6, what is the probability of choosing numbers 1, 2, and 3?
My approach: because order doesn't matter I used the combination 6 choose 3 which equals 20 possible combinations. Then there is only one combination out of these 20 that has 1, 2, and 3 so the probability is 1/20. Is that right?
If anyone can post with an explanation that would be fantastic.












