Problem on percentage

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Problem on percentage

by guerrero » Mon Dec 03, 2012 11:55 am
In the year 2001, a company's sales increased by x percent from the year 2000. In 2002, sales decreases x percent from the year 2001. If the sales in 2002 is 9 percent less than that in 2000, what is x?

please help me with the approach.

thanks,
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by Anindya Madhudor » Mon Dec 03, 2012 12:06 pm
Let's say company sales in 2000 is $1.

In 2001, company sales will be 1 * (1 + x/100) = 1+ x/100
In 2002, company sales will be (1+x/100) * (1-x/100) = 1- (x^2)/ 100^2

Sales in 2002 is equal to 91% of sales in 2000 as per the question.

So, 0.91 = 1- (x^2)/ 100^2
Solve this for x. x= 30%.

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by GMATGuruNY » Mon Dec 03, 2012 1:00 pm
guerrero wrote:In the year 2001, a company's sales increased by x percent from the year 2000. In 2002, sales decreases x percent from the year 2001. If the sales in 2002 is 9 percent less than that in 2000, what is x?

20
30
40
50
60
I've added answer choices, which an actual GMAT question would provide.
Let the sales in 2000 = 100.
We can plug in the answers for the value of x.

Answer choice C: 40
Sales in 2001 = 100 + .4(100) = 140.
Sales in 2002 = 140 - .4(140) = 84.
From 100 to 84 is a decrease of 16%.
Since the decrease is supposed to be only 9%, the value of x must be smaller.
Eliminate C, D and E.

Answer choice B: 30
Sales in 2001 = 100 + .3(100) = 130.
Sales in 2002 = 130 - .3(130) = 91.
From 100 to 91 is a decrease of 9%.
Success!

The correct answer is B.

If a value increases by x% and then decreases by y%, the total percent change = x - y - xy/100.

Thus:
If a value increases by x% and then decreases by x%, the total percent change = x - x - x²/100 = -x²/100.

Here, the total percent change = -9%.
Thus:
-x²/100 = -9
x² = 900
x = 30.
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