Viper83 wrote:Pat, Kate and Mark charged a total of 162 hours to a certain project. If Pat charged twice as much time to the project as Kate and 1/3 as much as Mark, how many more hours did mark charge to the project than Kate?
a) 18
b) 36
c) 72
d) 90
e) 108
D
We can plug in values in order to determine the ratio of K: P :M.
If K=1, then P=2 (since Pat charged twice as much), and M=6 (since Pat charged 1/3 as much as Mark).
Thus, K: P :M = 1:2:6. Since 1+2+6=9, Kate charged 1/9 of the total time.
K = 1/9 * 162 = 18.
Following the ratio above, M = 6K = 6*18 = 108.
M-K = 108-18 = 90.
The correct answer is
D.
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