If n is multiple of 5 and n = p^2q, where p and q are prime numbers, which of the following must be a multiple of 25?
p^2
q^2
pq
p^2q^2
p^3q
p^2
q^2
pq
p^2q^2
p^3q
If p and q are prime numbers, and p²q is divisible by 5, then either p = 5, q = 5 or they both equal 5.josh80 wrote:If n is multiple of 5, and n = p²q, where p and q are prime numbers, which of the following MUST be a multiple of 25?
A) p²
B) q²
C) pq
D) p²q²
E) p³q
We're looking for an expression that MUST be divisible by 25, which means there must be TWO 5's "hiding" in the expression.
A) p²
We cannot be certain that there are TWO 5's "hiding" in this expression.
It could be the case that p = 2 and q = 5, in which case p² is NOT divisible by 25
ELIMINATE A
B) q²
We cannot be certain that there are TWO 5's "hiding" in this expression.
It could be the case that p = 5 and q = 2, in which case q² is NOT divisible by 25
ELIMINATE B
C) pq
We cannot be certain that there are TWO 5's "hiding" in this expression.
It could be the case that p = 5 and q = 2, in which case pq is NOT divisible by 25
ELIMINATE C
D) p²q²
YES, we can be certain that there are TWO 5's "hiding" in this expression.
If p = 5, then p²q² = 25q², which is DEFINITELY divisible by 25
If q = 5, then p²q² = 25p², which is DEFINITELY divisible by 25
E) p³q
We cannot be certain that there are TWO 5's "hiding" in this expression.
It could be the case that p = 2 and q = 5, in which case p³q is NOT divisible by 25
ELIMINATE E
Answer = D
Cheers,
Brent
