The only items in a container A are 150 pencils and 725 pens. The ratio of the number of pencils to the number of pens in container B is 2 to 3. If all the pencils and pens in container B are placed in container A, then the ratio of the number of pencils to the number of pens in container A would be 3 to 5. What is the total number of pencils and pens in both container A and container B ?
a.5,600
b.6,725
c.7,125
d.7,275
e.8,000
I've set up the following equations from the question stem:
1. c/n=2/3 (where c=# of pencils in cont. B and n=# of pens in cont. B)
2. (c+150)/(n + 725)=3/5
then, solving for c = 1425, and n=4275. Adding them together, I got 7125, which is choice c. But, the answer is e. 8000. What am i doing wrong?
Thanks.
a.5,600
b.6,725
c.7,125
d.7,275
e.8,000
I've set up the following equations from the question stem:
1. c/n=2/3 (where c=# of pencils in cont. B and n=# of pens in cont. B)
2. (c+150)/(n + 725)=3/5
then, solving for c = 1425, and n=4275. Adding them together, I got 7125, which is choice c. But, the answer is e. 8000. What am i doing wrong?
Thanks.
