M7MBA wrote:
The equilateral triangle ABC is inscribed within a circle as shown above. If the circle has an area of 36Ï€, what is the length of minor arc AC?
A. 3Ï€
B. 4Ï€
C. 5Ï€
D. 6Ï€
E. 9Ï€
[spoiler]OA=B[/spoiler]
We know that the area of a circle is πr^2 = 36π. Thus, r = radius = 6.
Thus, the circumference of the circle = 2Ï€r = 2Ï€*6 = 12Ï€
Since ∆ABC is an equilateral triangle, all the three arcs AB, BC, and CA are equal, thus, the length of minor arc AC = 12π/3 = 4π
The correct answer: B
Hope this helps!
-Jay
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The equilateral triangle ABC is inscribed within a circle as
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Minor arc AC is 1/3 of the circumference.
Since the area of the circle is 36Ï€, the radius is 6, and thus, the circumference is 12Ï€. Minor arc AC is therefore 1/3 x 12Ï€ = 4Ï€.
Answer: B
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