Difficult function

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Difficult function

by Sandman » Tue Sep 09, 2008 1:14 am
For which of the following functions is f(a+b)= f(a) + f(b) true for all positive numbers a and b?

a.f(x)=x^2
b.f(x)=x+1
c.f(x)=rootunder x
d.f(x)=x/2
e.f(x)=-3x

Can anyone please explain this one.....
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I see two correct answers here!

by rogue_rohit » Tue Sep 09, 2008 1:38 am
Substitute (a+b) in place of x in each of the following functions and then try try to express it term of f(a) and f(b) and see if it is equal to f(a)+f(b)

for example
(a) f(x)=x^2
Substituting (a+b) in place of x gives f(a+b)= (a+b)^2 = (a^2) + (b^2) +2a*b = f(a) + f(b) +2*a*b --------- (hence not a correct option)
similarly

(b) f(x)=x+1
After substitution f(a+b) = a+b+1 = (a+1) + (b+1) -1 = f(a)+f(b) -1 ----------- (Hence again not a correct option)

(c) rootunder x
After substitution f(a+b)= rootunder(a+b) which is not equal to rootunder(a) +rootunder(b) ----------- (Hence again not a correct option)

(d) f(x)=x/2
After substitution f(a+b)= (a+b)/2 = (a/2) + (b/2) = f(a) + f(b) ----------Hence the correct answer


(e) f(x)=-3x
After substitution f(a+b)= -3(a+b) = -3a -3b = (-3a) + (-3b) = f(a) + f(b) ---------- Again correct answer

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by Sandman » Tue Sep 09, 2008 2:21 am
Thanx parallel_chase and rogue_rohit..i get it now. :oops: