vaibhav101 wrote:If ⌈x⌉ denotes the least integer greater than or equal to x, is ⌈x⌉=0 ?
1. -1 < x < 1
2. x < 0
S1: pick some numbers in the range
Case 1: x = -1/2; If {-1/2] denotes the least integer greater than or equal to -1/2, then {-1/2] would be 0. So we get a YES. (Effectively, if x isn't an integer, we're just rounding up to the closest integer.)
Case 2: x = 1/2; If {1/2] denotes the least integer greater than or equal to 1/2, then {1/2] would be 1. So we get a NO. Not sufficient.
S2: Clearly not sufficient. x could be -1/2. Or x could be -100.
Together: Now we know that -1 < x < 0. No matter what value we pick for x, the smallest integer greater than x will be 0. (If x = -1/2 we round up to 0. If x = -1/8 we round up to 0, etc.) The answer is definitely YES, so together the statements are sufficient. The answer is
C
