Sum of digits

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by Anurag@Gurome » Fri Jan 28, 2011 12:53 am
diehard_gmat wrote:What is the sum of the digits of the decimal form of the product (2^2009 * 5^2011)?

A. 2
B. 4
C. 5
D. 7
E. 10
The product = (2^2009)*(5^2011) = (2^2009)*(5^2009)*(5^2) = (10^2009)*(5^2) = 25*(2009 zeroes after 1) = 25000.... (2009 zeroes)

Hence, sum of the digits of the product = (2 + 5) = 7

The correct answer is D.
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by diehard_gmat » Fri Jan 28, 2011 12:54 am
Thanks Anurag!
You're awesome! :D