This is one of the most difficult Inequality question.Check Ron's explanation in the below link,
https://www.manhattangmat.com/forums/is- ... t4655.html
BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course
Redeem
Featured Course
Target Test Prep GMAT OnDemand
Scott Woodbury-Stewart’s private virtual classroom — 400 hours of master-class video lessons for the GMAT Focus Edition.
- 715+ score guarantee — highest in the industry (99th percentile)
- 52 chapters · 1,500+ lessons · 4,000+ practice questions
- 400 hours of video · 1,500+ instructor-led HD smartboard lessons
- 300,000+ students accepted to Harvard, Stanford, Wharton, Booth & Sloan & more
- 24/7 live support + weekly Zoom office hours with GMAT instructors
- TTP AI Assist — 24/7 AI-powered virtual tutor for instant help
- 1,200+ flashcards + AI-powered study assistant & daily calendar
- OnDemand, LiveTeach & GMAT Bootcamp formats available
- Also: GRE, SAT Math & Executive Assessment courses
- MBA Admissions Consulting now available
- 🏆 2025 EdTech Breakthrough Award: Test Prep Solution Provider of the Year
- 200,000+ students served
- 5-day free trial — $0 to start, no auto-billing, cancel anytime
★★★★★
5.0
(559 reviews)
130-pt guarantee
$0 to start
then $127/mo
inequalities
Source: Beat The GMAT — Data Sufficiency |
Hey....thanks for the link. You're right it is a pretty difficult question. I'm not comfortable with this on even after Ron's distinct explanation 8(...guess i'll let it be
Ok let me try explain in simple way.
The trick here is finding values so that 2 cases of inequalties exists[>,<]
stmt1,
X^2 + Y^2 > Z^2
x=2,y=2,z=1.X^4+Y^y > Z^4
x=3,y=3,z=4,X^4+Y^y < Z^4
Insuff
stmt2,
x+y>z
x=1,y=1,z=0,X^4+Y^y > Z^4
x=2,y=2,z=3,X^4+Y^y < Z^4
Insuff
Combining 1 and 2,
x=2,y=2,z=1.X^4+Y^y > Z^4
x=3,y=3,z=4,X^4+Y^y < Z^4
Insuff
Pick E
Hope this clarify!!
The trick here is finding values so that 2 cases of inequalties exists[>,<]
stmt1,
X^2 + Y^2 > Z^2
x=2,y=2,z=1.X^4+Y^y > Z^4
x=3,y=3,z=4,X^4+Y^y < Z^4
Insuff
stmt2,
x+y>z
x=1,y=1,z=0,X^4+Y^y > Z^4
x=2,y=2,z=3,X^4+Y^y < Z^4
Insuff
Combining 1 and 2,
x=2,y=2,z=1.X^4+Y^y > Z^4
x=3,y=3,z=4,X^4+Y^y < Z^4
Insuff
Pick E
Hope this clarify!!
--Anand--
Got it!!! thanks for the explanation.....i guess it was'nt that tough after all....the only tough part would be picking numbers during the exam
