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YavuzSelim111
- Newbie | Next Rank: 10 Posts
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- Joined: Fri Feb 21, 2014 7:00 pm
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Hi there, I am having difficulty in trying to under how to work this problem. Any help would be appreciated. Thanks in advance:
Jane must select three different items for each dinner she will serve. The items are to be chosen from among 5 different vegetarian and 4 different meat selections. If at least one of the selections must be vegetarian, how many different dinners could Jane create?
A 30
B 40
C 60
D 70
E 80
What I did: Total Possible Dinners choices - Only Meat Selections = At least one selection veg
= 9!/6! - 4!/1! = 9*8*7 - 4*3*2 = At least one selection is veg = 21, but 21 is not even in the answer choices. Where am I going wrong?
Jane must select three different items for each dinner she will serve. The items are to be chosen from among 5 different vegetarian and 4 different meat selections. If at least one of the selections must be vegetarian, how many different dinners could Jane create?
A 30
B 40
C 60
D 70
E 80
What I did: Total Possible Dinners choices - Only Meat Selections = At least one selection veg
= 9!/6! - 4!/1! = 9*8*7 - 4*3*2 = At least one selection is veg = 21, but 21 is not even in the answer choices. Where am I going wrong?












