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Prob

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by heshamelaziry » Wed Nov 04, 2009 6:05 pm
A team has a record of 12 wins and 13 losses for the season. Three games remain. If the probability of winning each remaining game is 1/2, and there are no draws, what is the probability that the team will finish the season with a winning record ?

1/8

1/4

3/8

1/2

5/8
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by crackthetest » Wed Nov 04, 2009 8:20 pm
1/4

The team needs atleast 2 wins, so the prob is 1/2*1/2.
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Re: Prob

by heshamelaziry » Wed Nov 04, 2009 8:37 pm
heshamelaziry wrote:A team has a record of 12 wins and 13 losses for the season. Three games remain. If the probability of winning each remaining game is 1/2, and there are no draws, what is the probability that the team will finish the season with a winning record ?

1/8

1/4

3/8

1/2

5/8
[spoiler]OA 1/8[/spoiler]
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by jaspreet_takhar » Wed Nov 04, 2009 8:59 pm
The team needs to win the remaining 3 matches to get a score of 15-13..
so , 1/8 is right
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by heshamelaziry » Wed Nov 04, 2009 9:24 pm
jaspreet_takhar wrote:The team needs to win the remaining 3 matches to get a score of 15-13..
so , 1/8 is right
But the team only need ttwo wins to be 14-13 ?
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by crackgmat007 » Wed Nov 04, 2009 9:52 pm
heshamelaziry wrote:
jaspreet_takhar wrote:The team needs to win the remaining 3 matches to get a score of 15-13..
so , 1/8 is right
But the team only need ttwo wins to be 14-13 ?
What if the last game is lost? It will be a draw. Since theq uestion requires us to calculate the probability that the team will finish the season with a winning record , all three games need to be considered.

Hope it clarifies.
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by antondesh » Thu Nov 05, 2009 12:44 pm
Yeah it should be 1/8.

Think about it. The team is has 12 wins, 13 losses. 3 games remain.

If they win 2 and lose 1, their final record will be 14 wins, 14 losses.

So they will need to win of their remaining games. Probablily of that is 1/2 * 1/2 * 1/2 = 1/8.
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