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GMAT Prep: Numbers

Expert replies
Source: — Data Sufficiency |

by shovan85 » Sat Oct 02, 2010 3:33 am
IMO C

These kind of problems think or draw a number line then try to put the possible values m and z without violating the inequalities.

from 1: m-3z>0 => m>3z
but we cannot say e=whether m and z are +ve or negative. (say m = -2,z=-1 then m>3z but m+z < 0)

from 2: 4z > m still we cannot say whether m+z > 0.

Combine 1 and 2 we can get 4z>m>3z. this pattern is only valid when m and z both are + ve. so m + z > 0

Hope this helps
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by Rahul@gurome » Sat Oct 02, 2010 3:49 am
(1) If m = 15 and z = 4, then m + z = 19 > 0
If m = -9 and z = -4, then m + z = -13 < 0
No unique answer.
So, (1) is NOT SUFFICIENT.

(2) If m = 2 and z = 1, then m + z = 3 > 0
If m = -9 and z = -2, then m + z = -11 < 0
No unique answer.
So, (2) is NOT SUFFICIENT.

Combining (1) and (2), m - 3z > 0 or m > 3z and 4z - m > 0 m < 4z
So, 3z < m < 4z
If we take z = -1, then 3z < m < 4z does not hold true. It is true only for positive values of z, and when z is positive, m is also positive. hence m + z > 0

The correct answer is [spoiler](C)[/spoiler].
Rahul Lakhani
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by GMATMadeEasy » Sat Oct 02, 2010 2:43 pm
Also, adding 1 and 2 gives z > 0.
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