I would say C
is b^m = some integer * a^k
Stmt I
b = k*a
Is (ka) ^m = some integer * a^k
Is k^m * a^m / a^k = some integer
We dont know since m>k or m<k (k^m is always an integer)
INSUFF
Stmt II
m>k
No idea about a and b
INSUFF
Together:
Is k^m * a^m / a^k = some integer
yes
a^m / a^k is an integer since m>k so k^m (int) * a^m / a^k (int) = integer
multiple
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Source: Beat The GMAT — Data Sufficiency |
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rahulg83
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I simply plugged in few values..
Obviously none of them alone is sufficient
Suppose a=5, b=15 (as per st I)
St II m>k, lets take m=3, k=2
only when m=1, k=2 will b^m will not be a multiple of a^k, u can check will all the other values
But what if m=-1 and k=-2 (we don't know whether m and k are positive)
b^m = 1/15; a^k = 1/25, 1/15 is not a multiple of 1/25
hence E
Please somebody correct me if i am wrong anywhere..
Obviously none of them alone is sufficient
Suppose a=5, b=15 (as per st I)
St II m>k, lets take m=3, k=2
only when m=1, k=2 will b^m will not be a multiple of a^k, u can check will all the other values
But what if m=-1 and k=-2 (we don't know whether m and k are positive)
b^m = 1/15; a^k = 1/25, 1/15 is not a multiple of 1/25
hence E
Please somebody correct me if i am wrong anywhere..
