Relatively new GMAT PREP QUESTION

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cramya: Legendary Member; Posts: 2467; Joined: Thu Aug 28, 2008 6:14 pmFollowed by: 11 members; Thanked: 331 times

by cramya » Thu May 07, 2009 4:51 pm

Q Each of the W,X,Y,Z are either 0 or 1. What is the value of w + x + y + z ?
1) w/2 + x/4 + y/8 + z/16 = 11/16
2) w/3 + x/9 + y/27 + z/81 = 31/81

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Source: Beat The GMAT — Data Sufficiency | Thu May 07, 2009 4:51 pm

kanha81: Master | Next Rank: 500 Posts; Posts: 431; Joined: Sat Jan 10, 2009 9:32 amFollowed by: 1 member; Thanked: 16 times

Re: Relatively new GMAT PREP QUESTION

by kanha81 » Thu May 07, 2009 5:05 pm

cramya wrote:Q Each of the W,X,Y,Z are either 0 or 1. What is the value of w + x + y + z ?
1) w/2 + x/4 + y/8 + z/16 = 11/16
2) w/3 + x/9 + y/27 + z/81 = 31/81

this is how I would approach:

1) w=1, x=0, y=1, z=1
1/2 + 0 + 1/8 + 1/16 = (8+2+1) / 16 = 11/16

Suff

2) w=1, x=0, y=1, z=1
1/3 + 0 + 1/27 + 1/81 = (27+3+1) / 81 = 31/81

Suff

[spoiler][D][/spoiler]

I am pretty sure there is more than meets the eye! [/spoiler]

Want to Beat GMAT.
Always do what you're afraid to do. Whoooop GMAT

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aj5105: Legendary Member; Posts: 1169; Joined: Sun Jul 06, 2008 2:34 amFollowed by: 1 member; Thanked: 25 times

by aj5105 » Thu May 07, 2009 11:31 pm

yup, I got (D)

I got 3 in both cases. Something tricky in here

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ajaypatil_am: Senior | Next Rank: 100 Posts; Posts: 81; Joined: Sat Jan 27, 2007 5:18 am; Location: PUNE

by ajaypatil_am » Thu May 07, 2009 11:41 pm

cramya - please let us know OA and OE (if u hv)

https://ajaypatil.wordpress.com/

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Vemuri: Legendary Member; Posts: 682; Joined: Fri Jan 16, 2009 2:40 amFollowed by: 1 member; Thanked: 32 times

Re: Relatively new GMAT PREP QUESTION

by Vemuri » Fri May 08, 2009 1:37 am

cramya wrote:Q Each of the W,X,Y,Z are either 0 or 1. What is the value of w + x + y + z ?
1) w/2 + x/4 + y/8 + z/16 = 11/16
2) w/3 + x/9 + y/27 + z/81 = 31/81

IMO D. This question seems straight forward.

Stmt1: 8w+4x+2y+z=11. We know that W,X,Y,Z are either 0 or 1. So, the only possible option is when w=1,x=0,y=1,z=1. Sufficient

Stmt1: 27w+9x+3y+z=31. We know that W,X,Y,Z are either 0 or 1. So, the only possible option is when w=1,x=0,y=1,z=1. Sufficient

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cramya: Legendary Member; Posts: 2467; Joined: Thu Aug 28, 2008 6:14 pmFollowed by: 11 members; Thanked: 331 times

by cramya » Fri May 08, 2009 8:46 pm

OA : D

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