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What is the median?

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by engg.manik » Thu Sep 24, 2009 11:30 pm
If the max number is 25 then the series should be

from -24, -23 ,-22 ..... 0 , 1 , ...25.

It also satisfies the second condition min + max = 1.

Now the median will be (0 + 1)/ 2 = 0.5
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by ern5231 » Fri Sep 25, 2009 4:05 am
This is a DS question. The OA given is D but I feel the answer is A.
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Re: What is the median?

by Brent@GMATPrepNow » Fri Sep 25, 2009 6:35 am
ern5231 wrote:There are 50 continuous integers in a series. What is the median of the series?

a) Max number is 25
b) Sum of the biggest and the smallest number is 1
(a)From here we can determine that the numbers range from -24 to 25. Since we know all 50 numbers, we can determine the median --> SUFF

(b) let x = the smallest integer
x+1 = 2nd integer
x+2 = 3rd integer
.
.
.
x+49 = 50th (last) integer
From the statement we can write the equation x + (x+49)=1
We can solve this equation to get x=-24.
Now that we know the first number is -24, we can determine that the last number is 25.
Since we know all 50 numbers, we can determine the median --> SUFF

Answer=D
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by ern5231 » Fri Sep 25, 2009 5:57 pm
Thanks Brent but suppose we have a series : -49 to 0 then the median is not the same as obtained above. In that case the again the answer should be A. Where am I going wrong?
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by Brent@GMATPrepNow » Sat Sep 26, 2009 1:58 pm
ern5231 wrote:Thanks Brent but suppose we have a series : -49 to 0 then the median is not the same as obtained above. In that case the again the answer should be A. Where am I going wrong?
Are you suggesting that the set of numbers from -49 to 0 satisfy the condition set out in statement (2)?
Here, the sum of the biggest and smallest numbers is not 1
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