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Classic combinatorics question

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by caspermonday » Thu Oct 22, 2009 3:34 am
There are 5 chairs and 4 women and 1 man. The man must sit in the centre chair. How many difference sitting arrangements are possible for the 5 people?

a. 4
b. 5
c. 20
d. 24
e. 120

OA D
Please explain
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by papgust » Thu Oct 22, 2009 3:47 am
Question says "The man must sit in the middle chair". However, since there is only 1 man we can just sideline this point and focus on arranging other 4 women in remaining 4 chairs.

This can be done in 4*3*2*1 ways for 4 remaining chairs. This equals 24 ways.

Please correct me if i'm wrong!
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by caspermonday » Thu Oct 22, 2009 5:25 am
Absolutely right!
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